How many moles of sebacoyl chloride do you have if you measure out 5 mL of a 9% volume/volume solution in cyclohexane?

moles sebacoyl chloride = 2.1 x 10-3 mol

Explanation:

Concentration sebacoyl chloride = 9% (v/v) = 9 mL sebacoyl chloride / 100 mL solution Volume of solution measured = 5 mL volume of sebacoyl chloride = (Volume of solution measured) * (Concentration sebacoyl chloride) volume of sebacoyl chloride = (5 mL) * (9 mL sebacoyl chloride / 100 mL solution) volume of sebacoyl chloride = (5 * 9) / 100 mL volume of sebacoyl chloride = 0.45 mL mass sebacoyl chloride = (volume of sebacoyl chloride) * (density of sebacoyl chloride) mass sebacoyl chloride = (0.45 mL) * (1.121 g/mL) mass sebacoyl chloride = 0.50445 g moles sebacoyl chloride = (mass sebacoyl chloride) / (molar mass sebacoyl chloride) moles sebacoyl chloride = (0.50445 g) / (239.14 g/mol) moles sebacoyl chloride = 2.1 x 10-3 mol