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24 July, 19:05

A 49.06-mL sample of an ammonia solution is analyzed by titration with HCl. The reaction is given below. NH3 (aq) + H + (aq) → NH4 + (aq) It took 39.66 mL of 0.0975 M HCl to titrate (react completely with) the ammonia. What is the concentration of the original ammonia solution?

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  1. 24 July, 22:23
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    0.0788 M

    Explanation:

    NH₃ (aq) + H⁺ (aq) → NH₄⁺ (aq)

    Because one mol of ammonia (NH₃) reacts with one mol of HCl, we can use the formula

    C₁V₁=C₂V₂

    Where V₁ and C₁ are the volume and concentration of the ammonia solution, respectively. While the subscript 2 refers to HCl. We're given V₁, C₂ and V₂; so we solve for C₁:

    C₁ = C₂V₂ / V₁ C₁ = 0.0975 M * 39.66mL / 49.06 mL C₁ = 0.0788 M
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