Calculate the molar mass of a gas if an 8.06*10 (to the power of - 2) gram sample of it occupies. 0650 L at 547°C and 70.5 kPa

M. Mass = 120 g/mol

Explanation:

Data Given:

Volume = V = 0.0650 L

Temperature = T = 547 °C = 820.15 K

Pressure = P = 70.5 kPa = 0.695 atm

Gas Constant = R = 0.082057 L. atm. mol⁻¹. K⁻¹

Formula Used:

Assuming that the gas is ideally then according to ideal gas equation,

P V = n R T

Solving for n,

n = P V / R T

Putting Values,

n = (0.695 atm * 0.0650 L) : (0.082057 L. atm. mol⁻¹. K⁻¹ * 820.15 K)

n = 6.71 * 10⁻⁴ moles

Now, Knowing that,

Moles = Mass / M. Mass

Or,

M. Mass = Mass / Moles

Putting values,

M. Mass = 8.06 * 10⁻² g / 6.71 * 10⁻⁴ mol

M. Mass = 120 g/mol