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20 August, 05:05

If 9.96 L of gas at 13°C and 2.28 atm is compressed at a pressure of 133 atm and 29°C, calculate the

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  1. 20 August, 06:49
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    V₂ = 0.18 L

    Explanation:

    According to general gas equation:

    P₁V₁/T₁ = P₂V₂/T₂

    Given dа ta:

    Initial volume = 9.96 L

    Initial pressure = 2.28 atm

    Initial temperature = 13 °C (13 + 273 = 286 K)

    Final temperature = 29 °C (29 + 273 = 302 K)

    Final volume = ?

    Final pressure = 133 atm

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    Solution:

    P₁V₁/T₁ = P₂V₂/T₂

    V₂ = P₁V₁T₂ / T₁P₂

    V₂ = 2.28 atm * 9.96 L * 302 k / 286 K * 133 atm

    V₂ = 6858.1 L / 38038

    V₂ = 0.18 L
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