How many grams of H 3 PO 4 are produced when 10.0 moles of water react with an excess of P 4 O 10?

653.1 g of H₃PO₄ will be produced, by 10 moles of H₂O

Explanation:

P₄O₁₀ + 6H₂O → 4H₃PO₄

1 mol of phosphorus oxide reacts with 6 mol of water to produce 4 mol of orthophosphoric acid.

If 6 moles of water make 4 mol of acid

10 mol water, will make (10.4) / 6 = 6.67 moles of acid

Molar mass H₃PO₄ = 97.97 g/m

Mol. molar mass = mass → 6.67 moles. 97.97 g/m = 653.1 g