Ask Question
9 March, 22:16

245 g water sample initially at at 32 oC absorbs 17 kcal of heat. What is the final temperature of water?

+3
Answers (1)
  1. 10 March, 00:05
    0
    Answer:62.66°C or 235.66K

    Explanation:Q=McpT, the energy was given in calories so you first convert to Joules by multiplying the value in calories by 4.184J.

    17*4.184=71.128kJ.

    71.128kJ=mcpT

    71.128kJ=245*4.187 * (T-Tm)

    Tm is the final temperature of the mixture. The T is the temperature given which should be converted to Kelvin by adding 273 ... T=32+273=305K.

    71128J=245*4.187 * (305-Tm)

    71128=312873.575-1025.815Tm

    1025.815Tm=312873.575-71128

    1025.815Tm=241745.58

    Tm=241745.58/1025.815

    Tm=235.66K
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “245 g water sample initially at at 32 oC absorbs 17 kcal of heat. What is the final temperature of water? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers