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20 May, 16:14

Methanol (CH3OH) is the simplest of the alcohols. It is synthesized by the reaction of hydrogen and carbon monoxide

CO (g) + 2H2 (g) = CH3OH

If 500 mol of CO and 750 mol of H2 are present, which Is the limiting reactant?

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  1. 20 May, 16:35
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    By reacting carbon monoxide and hydrogen the formation of methanol takes place, the reaction is,

    CO (g) + 2H₂ (g) ⇔CH₃OH (g)

    Based on the given reaction, one mole of methanol is obtained by reacting one mole of carbon monoxide (CO) with the two moles of hydrogen (H₂). It is mentioned in the question that for the reaction 500 mol of carbon monoxide and 750 moles of hydrogen are present.

    Therefore for 500 moles of carbon monoxide, there is a requirement of 2 * 500 moles of hydrogen, which is equivalent to 1000 moles of hydrogen (H₂). However, only 750 moles of hydrogen is present. Therefore, the limiting reactant in the given case is H₂. The present moles of H₂ will react with 0.5 * 750 moles of CO = 375 mole of CO

    The additional or excess concentration of CO, which is the excess reactant will be, 500-375 = 125 moles.
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