What is the specific heat of a substance if 25 grams rises in temperature from 10 degrees Celsius to 25 degrees with the addition of 280 calories of energy

0.75 cal/g°c

Explanation:

for specific heat we have formula:

Amount of heat absorbed or released = mass x specific heat of a substance x change in temperature.

ΔQ=m x c x ΔT

where c = specific heat

m = mass of a substance

ΔT = total temperature

ΔQ = Amount of heat

so for specific heat,

c = ΔQ/mxΔT

c = 280/25x (25-10)

c = 280/375

c = 0.75 cal/g°c