For each set of values, calculate the missing variable using the ideal gas law.

P V T n

Set 1 2.61 atm 1.69 L 36.1 °C n₁

Set 2 302 kPa 2382 mL T₂ 3.23 mol

Set 3 P₃ 0.0250 m³ 288 K 1.08 mol

Set 4 782 torr V₄ 303 K 5.26 mol

1. n = 0.174mol

2. T = 26.8K

3. P = 1.02atm

4. V = 126.88L

Explanation:

1. P = 2.61atm

V = 1.69L

T = 36.1 °C = 36.1 + 273 = 309.1K

R = 0.082atm. L/mol / K

n = ?

n = PV / RT = (2.61x1.69) / (0.082x309.1)

n = 0.174mol

2. P = 302 kPa = 302000Pa

101325Pa = 1atm

302000Pa = 302000/101325 = 2.98atm

V = 2382 mL = 2.382L

T = ?

n = 3.23 mol

R = 0.082atm. L/mol / K

T = PV / nR = (2.98x2.382) / (3.23x0.082) = 26.8K

3. P = ?

V = 0.0250 m³ = 25L

T = 288K

n = 1.08mol

R = 0.082atm. L/mol / K

P = nRT/V = (1.08x0.082x288) / 25 = 1.02atm

4. P = 782 torr

760Torr = 1 atm

782 torr = 782/760 = 1.03atm

V = ?

T = 303K

n = 5.26 mol

R = 0.082atm. L/mol / K

V = nRT/P

V = (5.26x0.082x303) / 1.03 = 126.88L