How much heat is absorbed when 4.5g of ice at 0°C melts to water at 10°C?

Answer: 90.45 joules

Explanation:

The quantity of Heat Energy (Q) absorbed by ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of ice = 4.5g

C = 2.010 J/g°C (Though not provided, but the specific heat capacity of ice is 2.010 J/g°C)

Φ = (Final temperature - Initial temperature)

= 10°C - 0°C = 10°C

Then, Q = MCΦ

Q = 4.5g x 2.010 J/g°C x 10°C

Q = 90.45 joules

Thus, 90.45 joules of heat is absorbed by ice.