How many grams of Cu would have to react to produce 89.5 grams of Ag

Mass = 26.36 of Cu

Explanation:

The balance chemical equation for this single replacement reaction is,

Cu + 2 AgNO₃ → Cu (NO₃) ₂ + 2 Ag

Step 1: Calculate moles of Ag as;

Moles = Mass / A. Mass

Moles = 89.5 g / 107.86 g/mol

Moles = 0.8297 moles

Step 2: Find out moles of Cu as,

According to balance equation,

2 moles of Ag are produced by = 1 mole of Cu

So,

0.8297 moles of Ag will be produced by = X moles of Cu

Solving for X,

X = 0.8297 mol * 1 mol / 2 mol

X = 0.4148 moles of Cu

Step 3: Calculate Mass of Cu as;

Mass = Moles * A. Mass

Mass = 0.4148 mol * 63.54 g/mol

Mass = 26.36 of Cu