How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess

3.62moles

Explanation:

First let us generate a balanced equation for the reaction

2Na + Cl2 - > 2NaCl

Molar Mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl from the balanced equation = 2 x 58.5 = 117g

From the question,

46g of Na produced 117g of NaCl.

Therefore, 83g of Na will produce = (83 x 117) / 46 = 211.11g of NaCl

Converting this mass (211.11g of NaCl) to mole, we obtain:

n = Mass / Molar Mass

n = 211.11 / 58.5

3.62moles