What must be the specific heat of a sample of an unknown material of 36.359g, when 59.912J of heat are applied raising the temperature 152°C?

0.0108 J/g°C

Explanation:

We are given;

Mass of the unknown material as 36.359 g Quantity of heat is 59.912 J Temperature change, ΔT = 152°C

We are required to calculate the specific heat capacity of the material.

Note that the quantity of heat absorbed is calculated by multiplying mass by specific heat and by change in temperature. Q = mcΔT

To calculate the specific heat capacity we rearrange the formula;

c = Q : mΔT

= 59.912 J : (36.359 g * 152°C)

= 0.0108 J/g°C

Therefore, the specific heat capacity of the unknown material is 0.0108 J/g°C