8 June, 10:54

# 1. Using the balanced equation, answer the following questions:2KClO3 → 2KCl + 3O2a. How many molecules of O2 will be formed from 34.35 grams of KClO3?b. How many grams of KCl will be formed from 52.53 grams of KClO3?

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1. 8 June, 13:35
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a) 2.53 * 10²³ molecules of O₂

b) 31.90 g of KCl

Explanation:

The balance chemical equation for given decomposition reaction is as follow;

2 KClO₃ → 2 KCl + 3 O₂

Part 1:

Step 1: Calculate Moles for given amount of KClO₃;

Moles = Mass / M. Mass

Moles = 34.35 g / 122.55 g/mol

Moles = 0.280 moles of KClO₃

Step 2: Find out moles of O₂ produced;

According to eq,

2 moles of KClO₃ produces = 3 moles of O₂

So,

0.280 moles of KClO₃ will produce = X moles of O₂

Solving for X,

X = 0.280 mol * 3 mol / 2 mol

X = 0.42 moles of O₂

Step 3: Calculate No. of Molecules of O₂ as,

No. of Molecules = Moles * 6.022 * 10²³

No. of Molecules = 0.42 mol * 6.022 * 10²³ molecules/mol

No. of Molecules = 2.53 * 10²³ molecules of O₂

Part 2:

Step 1: Calculate Moles for given amount of KClO₃;

Moles = Mass / M. Mass

Moles = 52.53 g / 122.55 g/mol

Moles = 0.428 moles of KClO₃

Step 2: Find out moles of KCl produced;

According to eq,

2 moles of KClO₃ produces = 2 moles of KCl

So,

0.428 moles of KClO₃ will produce = X moles of KCl

Solving for X,

X = 0.428 mol * 2 mol / 2 mol

X = 0.428 moles of KCl

Step 3: Calculate Mass of KCl as;

Mass = Moles * M. Mass

Mass = 0.428 mol * 74.55 g/mol

Mass = 31.90 g of KCl