Ask Question
7 November, 01:06

What is the sum of the numbers of neutrons and electrons in the ion 208 Pb2+?

+5
Answers (1)
  1. 7 November, 02:27
    0
    For ²⁰⁸Pb²⁺ cation, the sum of the number of neutrons and electrons = 206

    Explanation:

    Lead, chemical symbol Pb, is a chemical element which belongs to the group 14 of the periodic table. The atomic number of lead is 82 and it is a member of the p-block.

    The isotope of lead with the mass number 208, has 126 neutrons.

    Since, atomic number = number of protons = number of electrons for neutral atom

    Therefore, for ²⁰⁸Pb: number of electrons = 82

    So, for ²⁰⁸Pb²⁺ cation: number of electrons = 82 - 2 = 80

    Therefore, for ²⁰⁸Pb²⁺ cation, the sum of the number of neutrons and electrons = number of electrons + number of neutrons = 80 electrons + 126 neutrons = 206.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the sum of the numbers of neutrons and electrons in the ion 208 Pb2+? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers