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28 August, 09:08

PbS (s) + 4H2O2 (aq) →PbSO4 (s) + 4H2O (l) PbS (s) + 4H2O2 (aq) →PbSO4 (s) + 4H2O (l) Express your answers as chemical symbols separated by a comma. Enter the oxidized element first.

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  1. 28 August, 09:40
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    Sulphur is oxidised

    Hydrogen is reduced

    Explanation:

    Equation of the reaction

    PbS (s) + 4H2O2 (aq) → PbSO4 (s) + 4H2O (l)

    For Sulphur in PbS:

    +2 + S = 0

    S = - 2

    in PbSO4

    +2 + S + (4 * - 2) = 0

    S = + 6

    Sulphur is oxidised.

    For Hydrogen in H2O2:

    2H + (2 * - 2) = 0

    H = + 2

    in H2O

    H + (-2 * 1) = 0

    H = + 1

    Hydrogen is reduced.
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