PbS (s) + 4H2O2 (aq) →PbSO4 (s) + 4H2O (l) PbS (s) + 4H2O2 (aq) →PbSO4 (s) + 4H2O (l) Express your answers as chemical symbols separated by a comma. Enter the oxidized element first.

Question

Chemistry

Makayla Erickson

28 August, 09:08

PbS (s) + 4H2O2 (aq) →PbSO4 (s) + 4H2O (l) PbS (s) + 4H2O2 (aq) →PbSO4 (s) + 4H2O (l) Express your answers as chemical symbols separated by a comma. Enter the oxidized element first.

+2

Answers (1)

Know the Answer?

Roland · Answer 1

Sulphur is oxidised

Hydrogen is reduced

Explanation:

Equation of the reaction

PbS (s) + 4H2O2 (aq) → PbSO4 (s) + 4H2O (l)

For Sulphur in PbS:

+2 + S = 0

S = - 2

in PbSO4

+2 + S + (4 * - 2) = 0

S = + 6

Sulphur is oxidised.

For Hydrogen in H2O2:

2H + (2 * - 2) = 0

H = + 2

in H2O

H + (-2 * 1) = 0

H = + 1

Hydrogen is reduced.