Ask Question
30 June, 15:04

The stepwise formation constants for complexes of NH3 with [Cu (OH2) 6]2 + (aq) are logK11 = 4.15, log K12 = 3.50, log K13 = 2.89, log K14 = 2.13, log K15 = - 0.52. Suggest a reason why Kt5 is so different? (10)

+5
Answers (1)
  1. 30 June, 17:39
    0
    K₅ is smaller because the reaction is slower due to steric and electronic effects.

    Explanation:

    K is the rate constant of the reaction. The higher the value of log K, the higher the value of K and the faster is the reaction.

    The reaction can be represented by the following reaction:

    6 NH₃ + [Cu (OH₂) ₆]²⁺ → [Cu (NH₃) ₆]²⁺ + 6 H₂O

    This means that the reaction is exchanging the H₂O ligands by NH₃ ligands.

    The more NH₃ ligands we add to the complex, the more difficult (slower) is the substitution. This happend because the addition of NH₃ ligands promotes a steric hindrance and electronic repulsion, which makes it harder for the next NH₃ to approach the complex and substitute the H₂O ligand.

    This is the reason why K₅ is negative. The rate of this substitution is extremelhy low.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The stepwise formation constants for complexes of NH3 with [Cu (OH2) 6]2 + (aq) are logK11 = 4.15, log K12 = 3.50, log K13 = 2.89, log K14 ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers