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20 August, 23:32

How many grams of NO will be produced from 60.0g of NO2 reacted with excess water in the following chemical reaction?

3NO2 (g) + H2O (l) - -> 2HNO3 (g) + NO (g)

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  1. 21 August, 00:49
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    Mass = 19.78 g

    Explanation:

    Given dа ta:

    Mass of NO produced = ?

    Mass of NO₂ reacted = 60.0 g

    Solution:

    Chemical equation:

    3NO₂ (g) + H₂O (l) → 2HNO₃ (g) + NO (g)

    Number of moles of NO₂:

    Number of moles = mass/molar mass

    Number of moles = 60.0 g / 46 g/mol

    Number of moles = 1.3 mol

    Now we will compare the moles of NO₂ with NO.

    NO₂ : NO

    3 : 1

    1.3 : 1/3*1.3 = 0.43 mol

    Mass of NO:

    Mass = number of moles * molar mass

    Mass = 0.43 mol * 46 g/mol

    Mass = 19.78 g
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