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9 November, 03:37

Consider a situation in which 211 g

g

of P4

P

4

are exposed to 240 g

g

of O2

O

2

. What is the maximum amount in moles of P2O5

P

2

O

5

that can theoretically be made from 211 g

g

of P4

P

4

and excess oxygen?

Express your answer to three significant figures and include the appropriate units.

+1
Answers (1)
  1. 9 November, 03:54
    0
    3.00 mol

    Explanation:

    Given dа ta:

    Mass of P₄ = 211 g

    Mass of oxygen = 240 g

    Moles of P₂O₅ = ?

    Solution:

    Chemical equation:

    P₄ + 5O₂ → 2P₂O₅

    Number of moles of P₄:

    Number of moles = mass / molar mass

    Number of moles = 211 g / 123.88 g/mol

    Number of moles = 1.7 mol

    Number of moles of O₂:

    Number of moles = mass / molar mass

    Number of moles = 240 g / 32g/mol

    Number of moles = 7.5 mol

    Now we will compare the moles of product with reactant.

    O₂ : P₂O₅

    5 : 2

    7.5 : 2/5*7.5 = 3.00

    P₄ : P₂O₅

    1 : 2

    1.7 : 2*1.7 = 3.4 mol

    Oxygen is limiting reactant so the number of moles of P₂O₅ are 3.00 mol.

    Mass of P₂O₅:

    Mass = number of moles * molar mass

    Mass = 3 mol * 283.9 g/mol

    Mass = 852 g
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