17)

How many grams are in 0.02 moles of beryllium iodide, Bel2?

Answer: 5.26 g BeI2

Explanation: For 1 mole of BeI2 it is to its molar mass

Be mass is 9 and I mass is 127 x 2

The molar mass is 263 g BeI2

Solution:

0.02 moles BeI2 x 263 g BeI2 / 1 mole BeI2

= 5.26 g BeI2

beryllium iodide has a molar mass of 262.821 g mol-1, which means that 1 mole of beryllium iodide has a mass of 262.821 g. To find the mass of 0.02 moles of beryllium iodide, simply multiply the number of moles by the molar mass in conversion factor form.