An aerosol can contains 800.0 mL of compressed gas at 10.2 atm pressure. When the gas is sprayed into a large plastic bag, the bag inflates to a volume of 4.14 L. What is the pressure of gas (atm) inside the plastic bag if the temperature did not change and all of the gas was transferred completely?

The pressure of the gas inside the plastic bag is 1.971 atm

Explanation:

Since temperature did not change, it means it is constant. This will then be Boyle's law. Thus

P1V1 = P2V2

Where P1 is the initial pressure = 10.2 ATM, P2 is the final pressure which is to be calculated.

V1 is the initial volume = 800.0 mL and V2 is the final volume of the gas = 4.14 L

From the formula,

P2 = P1V1/V2

= 10.2*800:4.14

= 1.971 atm

Pressure of gas in the plastic bag is 1.97 atm

Explanation:

It is possible to answer this question by using Boyle's law: Boyle's law describes that, for ideal gases, the pressure of the gas is inversely proportional to the volume it occupies. Is expressed as:

P1V1 = P2V2

Where:

P1 is the initial pressure of the gas (In the problem, 10.2 atm).

V1 is initial volume (800.0mL)

V2 is final volume (4.14L ≡ 4140mL)

And P2 is the final pressure.

Replacing:

10.2 atm*800.0mL = 4140mL*P2

P2 = 1.97 atm