Which of the following will occur when a solution of Pb (NO3) 2 (aq) is mixed with a solution of KI (aq) ?

A.) A precipitate of KNO3 will form; Pb2 + and I - are spectator ions.

B.) A precipitate of Pb (NO3) 2 will form; K + and I - are spectator ions.

C.) A precipitate of PbI2 will form; Pb2 + and I - are spectator ions.

D.) A precipitate of PbI2 will form; K + and NO3 - are spectator ions.

E.) No precipitate will form.

When a solution of Pb (NO3) 2 (aq) is mixed with a solution of KI (aq), a precipitate of PbI₂ will form; K⁺ and NO₃⁻ are spectator ions.

Explanation:

When an aqueous solution of lead nitrate (Pb (NO₃) ₂ is mixed with aqueous solution of potassium iodide (KI), then there is a precipitate formation of lead iodide (PbI₂), and the potassium (K⁺) ion and nitrate (NO₃⁻) ion acts as spectator ions that is ions do not involved in the reaction.

The reaction can be represented as,

Pb (NO₃) ₂ (aq) + 2 KI (aq) → PbI₂ (s) + 2KNO₃ (aq)

The ionic equation can be written as,

Pb²⁺ (aq) + 2 NO₃⁻ (aq) + 2 K⁺ (aq) + 2 I⁻ (aq) → PbI₂ (s) + 2K⁺ (aq) + 2NO₃⁻ (aq)

On both sides of the equation, we have K⁺ and NO₃⁻ ions, which gets cancelled, and these 2 ions are called as spectator ions.