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2 July, 22:41

How many calories of heat were added to 347.9 g of water to raise its temperature from 25oC to 55oC?

(put your answer in standard notation, not scientific notation)

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Answers (1)
  1. 3 July, 00:30
    0
    10437calories

    Explanation:

    The following data were obtained from the question given:

    M = 347.9g

    C = 4.2J/g°C

    T1 = 25°C

    T2 = 55°C

    ΔT = 55 - 25 = 30°C

    Q = ?

    Q = MCΔT

    Q = 347.9 x 4.2 x 30

    Q = 43835.4J

    Converting this to calories, we obtained the following:

    4.2J = 1 calorie

    43835.4J = 43835.4 / 4.2 = 10437calories
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