The solubility of a compound with a molecular weight of 233.2 is determined to be 27.9 g in 125.0 g of water at 398 K. Express this concentration in terms of molality. 0.957

0.960 m

Explanation:

Given data

Mass of the solute: 27.9 g Molar mass of the solute: 233.2 g/mol Mass of the solvent: 125.0 g = 0.1250 kg

First, we will calculate the moles of solute.

27.9 g * (1 mol/233.2 g) = 0.120 mol

The molality of the compound is:

m = moles of solute / kilograms of solvent

m = 0.120 mol / 0.1250 kg

m = 0.960 m