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4 June, 21:59

1.5L of water is boiled to steam at a temperature of 100°C and creates 3.5atm of pressure on the container. How many moles of steam is present?

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  1. 4 June, 22:40
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    Answer: 1.7 moles

    Explanation:

    Given that:

    Volume of water V = 1.5L

    (since 1 liter = 1dm3

    1.5L = 1.5dm3)

    Temperature T = 100°C

    Convert Celsius to Kelvin

    (100°C + 273 = 373K)

    Pressure P = 3.5 atm

    Number of moles of steam N = ?

    Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1

    Then, apply ideal gas equation

    pV = nRT

    3.5atm x 1.5dm3 = n x (0.0082 ATM dm3 K-1 mol-1 x 373K)

    5.25 = n x 3.06

    n = 5.25/3.06

    n = 1.7 moles

    Thus, 1.7 moles of steam is present
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