3. Hexane (C6H-2) is combusted in oxygen

Balanced Reaction:

a. How many moles of oxygen are needed to react with 1 mole of hexane?

b. How many molecules of carbon dioxide can be produced from 245.5

grams of hexane?

a) 9.5 moles of Oxygen

b) 1.029 * 10²⁵ Molecules

Explanation:

The balance chemical equation for said reaction is as follow:

2 C₆H₁₄ + 19 O₂ → 12 CO₂ + 14 H₂O

A)

According to equation,

2 moles of C₆H₁₄ are reacted with = 19 moles of O₂

So,

1 moles of C₆H₁₄ will react with = X moles of O₂

Solving for X,

X = 19 moles * 1 mole / 2 moles

X = 9.5 moles of Oxygen

B)

For this part first calculate moles of hexane as;

Moles = Mass / M. Mass

Moles = 245.5 g / 86.18 g/mol

Moles = 2.84 mole of Hexane

Secondly, find the number of moles of CO₂ as,

According to equation,

2 moles of C₆H₁₄ produced = 12 moles of CO₂

So,

2.84 moles of C₆H₁₄ will produce = X moles of CO₂

Solving for X,

X = 12 moles * 2.84 mole / 2 moles

X = 17.09 moles of CO₂

Lastly, calculate the number of molecules of CO₂ as,

Number of Molecules = Moles * 6.022 * 10²³ molecules/mole

Number of Molecules = 17.09 moles * 6.022 * 10²³ molecules/mole

Number of Molecules = 1.029 * 10²⁵ Molecules