Donald needs to produce 5000 milliliters of 32% alcohol solution. At his disposal he has 40% alcohol solution and 20% alcohol solution. How much of each does he need in order to produce his desired solution?

The answer to your question is 3 L of solution 40% and 2 L of solution 20%

Explanation:

Data

Final volume = Vf = 5000 ml = 5 L

Final concentration = Cf = 32%

Concentration 1 = C1 = 40%

Concentration 2 = C2 = 20%

Volume 1 = x

Volume 2 = 5 - x

Process

1. - Write an equation to solve this problem

VfCf = C1V1 + C2V2

2. - Substitution

32 (5) = 40x + 20 (5 - x)

3. - Solve for x

160 = 40x + 100 - 20x

160 - 100 = 40x - 20x

60 = 20x

60/20 = x

x = 3

Then, Volume 1 = 3 L

4. - Find Volume 2

Volume 2 = 5 - 3

Volume 2 = 2 L