3.4 moles of solid CuSO4 is added to 1.8 L of water and allowed to dissolve. Will all the solid dissolve?

Yes, all the solid will dissolve.

Explanation:

To solve this problem we will first find the solubility of CuSO₄ at given temperature (in this case we will assume the temperature to be 20 °C. According to reported data 37.8 g of CuSO₄ can be dissolved in 100 ml of H2O at 20 °C.

While we are provided with moles of CuSO₄ and volume is given in Liters. So, we will convert moles to mass as,

Mass = Moles * Molar Mass

Mass = 3.4 mol * 159.60 g/mol

Mass = 542.64 g

Secondly, we will convert Liters to milliliters as,

Milliliters = Liters * 1000

Milliliters = 1.8 * 1000

Milliliters = 1800 ml

Therefore,

According to reference data,

37.8 g CuSO₄ dissolves in = 100 ml of water

So,

542.64 g CuSO₄ will dissolve in = X ml of water

Solving for X,

X = 542.64 g * 100 ml / 37.8 g

X = 1435.55 ml of Water

This means that we are provided with greater amount of water (i. e. 1800 m). Hence, the given amount of CuSO₄ will completely dissolve in 1.8 L of water and the solution formed is unsaturated and can dissolve further CuSO₄.