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27 October, 18:00

200 L of a gas at 10 atm pressure and 400 K is cooled to 100 K and reduced to 2 atm pressure. What is the new volume?

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  1. 27 October, 18:32
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    250L

    Explanation:

    Data;

    V1 = 200L

    P1 = 10atm

    T1 = 400K

    T2 = 100K

    P2 = 2atm

    V2 = ?

    To solve this question, we'll have to use the combined gas equation which is a combination of Boyle's law, Charles law and pressure law.

    From combined gas equation,

    (P1 * V1) / T1 = (P2 * V2) / T2

    P1 * V1 * T2 = P2 * V2 * T1

    Solve for V2,

    V2 = (P1 * V1 * T2) / P2 * T1

    V2 = (10 * 200 * 100) / (2 * 400)

    V2 = 200,000 / 800

    V2 = 250L

    The final volume of the gas is 250L
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