50.0 g of oxygen are advalible for the combustion of 25g of carbon is this an adequate anount if so by bow much in excessbis the oxygen if not by how much is the carbon in excess

6.25 g of Carbon is in Excess

Explanation:

The balance chemical equation is as follow:

C + O₂ → CO₂

Step 1: Calculate Moles of O₂ as:

Moles = Mass / M/Mass

Moles = 50 g / 32 g/mol

Moles = 1.562 mol of O₂

Step 2: Calculate Moles of C as;

Moles = 25 g / 12 g/mol

Moles = 2.08 mol

Step 3: Calculate the Limiting reagent:

According to equation,

1 moles of O₂ reacted with = 1 mole of C

So,

1.562 moles of O₂ will react with = X moles of C

Solving for X,

X = 1 mol * 1.562 mol / 1 mol

X = 1.562 mol of C

While we are provided with 2.08 mol of C. Means C is in excess.

Step 4: Calculate amount of Excess C as;

Excess Moles = Given Moles - Used Moles

Excess Moles = 2.08 mol - 1.562 mol

Excess Moles = 0.521 moles

Step 5: Converting Excess moles to Mass as:

Mass = Moles * M. Mass

Mass = 0.521 mol * 12 g/mol

Mass = 6.25 g