Glucose, C6 H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation C6H12O6 (aq) + 6O2 (g) ⟶ 6CO2 (g) + 6H2O.

1) Calculate the number of grams of oxygen required to convert 38.0 g of glucose to CO2 and H2O.

2) Also compute the number of grams of CO2 produced.

1. 40.5 grams of O₂ are needed in the reaction.

2. 55.4 grams of CO₂ are produced

Explanation:

C₆H₁₂O₆ (aq) + 6O₂ (g) ⟶ 6CO₂ (g) + 6H₂O

1 mol of glucose reacts with 6 moles of oxygen to produce 6 moles of carbon dioxide and 6 moles of water.

Ratio in the reactants is 1:6. Let's convert the mass of glucose to moles.

38 g / 180 g/mol = 0.211 moles

1 mol of glucose needs 6 moles of O₂ to react

Then, 0.211 moles would need (0.211. 6) / 1 = 1.26 moles

Let's convert the moles to mass of O₂

1.26 mol. 32 g / 1mol = 40.5 g

Ratio between oxygen and carbon dioxide is 6:6. Therefore is the same to say 1:1 → 6 moles of O₂ produce 6 moles of CO₂

Then, 1.26 moles of O₂ must produce 1.26 moles of CO₂

Let's convert the moles to mass → 1.26 mol. 44 g / 1mol = 55.4 g