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18 January, 08:03

A 453 g piece of glass at 25.7∘C is left outside on a sunny day. How much heat must the glass absorb from the sun in order to reach 40.3∘C?

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  1. 18 January, 10:35
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    Q = 5555.6J

    Explanation:

    Mass of glass piece, m = 453g

    initial temperature = 25.7°C

    temperature to be attained = 40.3°C

    ⇒change in temperature, Δt = 40.3 - 25.7 = 14.6°C

    specific heat of glass, s = 0.840J/g°C

    Heat absorbed, Q = msΔt

    ⇒Q = 453*0.840*14.6 = 5555.592J

    ⇒Q = 5555.6J (rounded to the nearest tenth)
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