Ask Question
4 August, 07:52

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. Suppose 7.22 g of ethane is mixed with 15. g of oxygen. Calculate the minimum mass of ethane that could be left over by the chemical reaction. Round your answer to significant digits.

+5
Answers (1)
  1. 4 August, 09:10
    0
    The remaining mass of ethane is 3.19 grams

    Explanation:

    Step 1: Data given

    Mass of ethane = 7.22 grams

    Mass of oxygen = 15.0 grams

    Molar mass ethane = 30.07 g/mol

    Molar mass oxygen = 32.0 g/mol

    Step 2: The balanced equation

    2C2H6 + 7O2 → 4CO2 + 6H2O

    Step 3: Calculate moles ethane

    Moles ethane = 7.22 grams / 30.07 g/mol

    Moles ethane = 0.240 moles

    Step 4: Calculate moles oxygen

    Moles oxygen = 15.0 grams / 32.0 g/mol

    Moles oxygen = 0.46875 moles

    Step 5: Calculate limiting reactant

    For 2 moles ethane we need 7 moles oxygen to produce 4 moles CO2 and 6 moles H2O

    Oxygen is the limiting reactant. It will completely be consumed (0.46875 moles). Ethane is in excess. There will react 0.46875 / 3.5 = 0.134 moles

    There will remain 0.240 - 0.134 = 0.106 moles

    Step 6: Calculate mass of remaining ethane

    Mass ethane = 0.106 moles * 30.06 g/mol

    Mass ethane = 3.19 grams

    The remaining mass of ethane is 3.19 grams
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. Suppose 7.22 g of ethane is mixed with ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers