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13 September, 10:08

The oxide of titanium, TiO2 is used as a "whitener" in toothpaste. It is obtained from the ore iron (II) titanate, FeTiO3. What is the change, if any, in the oxidation number (oxidation state) of titanium in the reaction

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  1. 13 September, 12:29
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    There is no change in the oxidation number (oxidation state) of titanium in the reaction

    Explanation:

    TiO2

    ⇒ The oxidation number of O = - 2

    ⇒ Since we have O2, this makes 2*-2 = - 4

    ⇒ The oxation number of Ti and O2 together should be 0

    ⇒The oxidation number of Ti is + 4

    For FeTiO3, it's more complicate because Fe can have several oxidation numbers.

    Since FeTiO3 has three short metal-oxygen bonds in the octahedron and three long metal - oxygen bonds.

    The valences, obtained from the bond lengths by the bond valence method, is + 2 anapproximately which can be rounded off to oxidation stated + 4, respectively for Fe and Ti.

    FeTiO3

    ⇒ The oxidation number of O = - 2

    ⇒ We have O3 so this makes 3*-2 = - 6

    ⇒Fe has an oxidation state of + 2

    ⇒The oxidation state of Fe, Ti and O3 together should be 0

    ⇒Ti has an oxidation state of + 4

    This means Titanium doesn't change it's oxidation number.

    There is no change in the oxidation number (oxidation state) of titanium in the reaction
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