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19 May, 03:35

What is the mass of 2.23 times 10^23 atoms of sulfur

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  1. 19 May, 06:37
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    The atomic mass of sulfur is 32.07 g/mole.

    1 mole of sulfur contains 6.022 * 10^23 atoms

    But 1 mole is equal to 32.07 g

    Therefore;

    6.022 * 10^23 atoms = 32.07

    Thus; 2.23 * 10^23 atoms = ?

    = (2.23 * 10^23 * 32.07) / 6.022*10^23

    = 11.876 g
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