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2 April, 06:47

The volume of a sample of oxygen is 200.0 mL when the pressure is 3.000 atm and the temperature is 37.0 oC. What is the new temperature if the volume increases to 400.0 mL and the pressure decreases to 2.000 atm

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  1. 2 April, 10:17
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    Given:

    V1 = 200 ml

    T1 = 20 °C

    = 20 + 273

    = 293 K

    P1 = 3 atm

    P2 = 2 atm

    V2 = 400 ml

    Using ideal gas equation,

    P1 * V1/T1 = P2 * V2/T2

    T2 = (2 * 400 * 293) / 200 * 3

    = 234400/600

    = 390.67 K

    = 390.67 - 273

    = 117.67 °C
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