Consider the titration of 30.0 mL of 0.050 M NH3 with 0.025 M HCl.

Calculate the after the following volumes of titrant have been added.

a) 0 mL

b) 20.0mL

c) 59.2mL

d) 60.0mL

e) 71.3mL

f) 73.3mL

60.0mL

Explanation:

For the process of titration, the formula we use is -

M₁V₁ = M₂V₂

Where,

M₁ = initial concentration

V₁ = initial volume

M₂ = final concentration

V₂ = final volume.

Hence, from the question,

The given data is,

M₁ = 0.050 M

V₁ = 30.0mL

M₂ = 0.025 M

V₂ = ?

Now, to determine the unknown quantity, the formula can be applied,

Hence,

M₁V₁ = M₂V₂

Putting the respective values,

0.050 M * 30.0mL = 0.025 M * ?

solving the above equation,

V₂ = ? = 60.0mL