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2 May, 04:26

7.) A syringe initially holds a sample of gas with a volume of 285 mL at 355 K and 1.88 atm. To

what temperature must the gas in the syringe be heated/cooled in order to have a volume of 435

mL at 2.50 atm?

A) 139 K

B) 572 K

C) 175 K

D) 466 K

E) 721 K

+2
Answers (1)
  1. 2 May, 05:16
    0
    T₂ = 721 k

    Explanation:

    Given dа ta:

    Initial volume = 285 mL

    Initial pressure = 1.88 atm

    Initial temperature = 355 K

    Final temperature = ?

    Final volume = 435 mL

    Final pressure = 2.50 atm

    Formula:

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = Initial pressure

    V₁ = Initial volume

    T₁ = Initial temperature

    P₂ = Final pressure

    V₂ = Final volume

    T₂ = Final temperature

    Solution:

    P₁V₁/T₁ = P₂V₂/T₂

    T₂ = P₂V₂ T₁ / P₁V₁

    T₂ = 2.50 atm * 435 mL * 355 K / 1.88 atm * 285 mL

    T₂ = 386062.5 atm. mL. K / 535.8 atm. mL

    T₂ = 721 k
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