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19 May, 02:03

what is the pH of a solution prepared from solid, neutral 2-nitrophenol providing a fromal concentration of 0.0353M, given that the Ka of 2nitrophenol is 5.98 x 10^-8

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  1. 19 May, 03:17
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    pH = 4.34

    Explanation:

    pH = - 1/2 (logKa) - 1/2 (log C)

    = - 1/2 (log 5.98*10^-8) - 1/2 (log 0.0353)

    =-1/2 (-7.22) - 1/2 (-1.45)

    =3.61+0.725 = 4.34
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