What mass of carbon dioxide gas occupies a volume of 8.13 L

at 204 kPa and a temperature of 95 0 °C?

23.76g

Explanation:

To solve for the mass of carbon dioxide (CO2), let us first obtain the number of mole of CO2.

From the question, the following were obtained:

V = 8.13L

P = 204kPa = 204000Pa

Recall: 101325Pa = 1atm

204000Pa = 204000/101325 = 2atm

T = 95°C = 95 + 273 = 368K

R = 0.082atm. L/K/mol

n = ?

PV = nRT

n = PV / RT

n = 2 x 8.13 / 0.082 x 368

n = 0.54mole

Now let us convert 0.54mole of CO2 to gram. This is illustrated below:

Molar Mass of CO2 = 12 + (16x2) = 12 + 32 = 44g/mol

Number of mole of CO2 = 0.54mole

Mass of CO2 = ?

Number of mole = Mass / Molar Mass

Mass = number of mole x molar Mass

Mass of CO2 = 0.54 x 44

Mass of CO2 = 23.76g