6Li (s) + N2=2LiN

the mass of N2 needed to react with. 536 moles of Li

Mass = 3.752 g

Explanation:

Given dа ta:

Number of moles of Li = 0.536 mol

Mass of N₂ needed = ?

Solution:

Chemical equation:

2Li + N₂ → 2LiN

Now we we will compare the moles of Li and N₂.

Li : N₂

2 : 1

0.536 : 1/2*0.536 = 0.268 mol

Mass of N₂

Mass = number of moles * molar mass

Mass = 0.268 mol * 14 g/mol

Mass = 3.752 g