How much dioxin is present in 3.0 L of this water? Assume a density of 1.00 g/mL. Express the answer in grams using two significant figures.

3000 grams

Explanation:

The formula to be used here is that of density

Density (g/ml) = mass (in grams) / volume (in milliliter)

The volume in the question will have to be converted to milliliter (mL), before been used in the formula above

1.0L = 1000 mL

3.0L = X

where X is the unknown

X = (3 * 1000) : 1

X = 3000mL

So, 3.0L = 3000mL (which is our volume)

Density = 1.00 g/mL

Hence,

1.00 = mass/3000

when cross multiplied, we have

mass = 3000 grams

Thus, 3000g of dioxin is present in 3.0L (3000 mL) of the water.