Ask Question
2 November, 20:26

Calculate the mass of CO2 produced by the combustion of a tank of gasoline. Assume the mass of gasoline is 46.0 kg and that gasoline is pure octane (C8H18).

+4
Answers (1)
  1. 2 November, 20:52
    0
    142035.09g

    Explanation:

    Let us write a balanced equation for the reaction. This is illustrated below:

    2C8H18 + 25O2 - > 16CO2 + 18H2O

    Molar Mass of C8H18 = (8x12) + (18x1) = 96 + 18 = 114g/mol

    Mass of C8H18 from the balanced equation = 2 x 114 = 228g

    Mass of C8H18 from the question = 46kg = 46 x 1000 = 46000g

    Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g

    Mass of CO2 from the balanced equation = 16 x 44 = 704g

    From the equation,

    228g of C8H18 produced 704g of CO2.

    Therefore, 46000g of C8H18 will produce = (46000 x 704) / 228 = 142035.09g of CO2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calculate the mass of CO2 produced by the combustion of a tank of gasoline. Assume the mass of gasoline is 46.0 kg and that gasoline is ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers