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10 July, 16:34

41. A 13.0% solution of K2CO3 by mass has a density of 1.09 g/cm3. Calculate the molality of the solution.

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  1. 10 July, 20:30
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    1.08 m is the molality of the solution.

    Explanation:

    1st step: Determine the mass of solvent.

    13% by mass means that 13 g are contained in 100 g of solution.

    Solution mass = Solute mass + solvent mass

    100 g = 13 g + Solvent mass

    Solvent mass = 100 g - 13 g → 87 g

    Second Step: Let's determine the moles of our solute mass (mass / molar mass)

    13 g / 138.2 g/mol = 0.094 moles

    Third step: Replace the data to determine molality.

    Molality are the moles of solute in 1kg of solvent (mol/kg)

    Before this, we must convert the solvent mass to kg

    87 g. 1kg / 1000 g = 0.087 kg

    molality → 0.094 mol / 0.087 kg = 1.08 m
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