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28 May, 02:32

If a gas in a closed container is pressurized from 14.0 atm to 17.0 atm and its original temperature was 30oC, what would the final temperature of the gas be

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  1. 28 May, 05:04
    0
    367.93K

    Explanation:

    P1 = 14atm

    P2 = 17atm

    T1 = 30oC = 273+30 = 303k

    T2=?

    Using Gay Lussac law

    P1/T1 = P2/T2

    14/303 = 17/x

    X = 367.93K
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