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11 August, 03:29

Write a balanced chemical equation between magnesium chloride and sodium phosphate. Determine the grams of magnesium chloride that are needed to produce 1.33 x 10^{23} formula units of magnesium phosphate.

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  1. 11 August, 05:33
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    The grams of MgCl₂ that are needed are 63.1 g

    Explanation:

    First of all, try to think the equation and ballance it. This is it:

    3MgCl₂ + 2Na₃PO₄ → Mg₃ (PO₄) ₂ + 6NaCl

    Let's convert our f. u in mol

    1 mol = 6.02x10²³ formula units (Avogadro's number)

    So f. u / Avogadro = mol

    1.33x10²³ / 6.02x10²³ = 0.221 moles.

    So 1 mol of phosphate sodium comes from 3 mol of magnesium chloride.

    How many mol of magnesium chloride are necessary, for 0.221 mol of phosphate.?

    0.221 moles. 3 = 0.663 moles.

    Molar mass of MgCl₂ is 95.2 g/m

    0.663 moles. 95.2 g/m = 63.1 g
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