a 280.0 mL sample of neon exerts a pressure of 660.0 toff at 26.0 celsius. at what temperture would it exert a pressure of 940.0 torr in a volume of 0.44 L

T₂ = 669.2 K

Explanation:

Given dа ta:

Initial pressure = 660 torr

Initial temperature = 26 °C (26 + 273 = 299 K)

Final volume = 280 mL (280/1000 = 0.28 L)

Final pressure = 940.0 torr

Final volume = 0.44 L

Final temperature = ?

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂ T₁ / P₁V₁

T₂ = 940 torr * 0.44 L * 299 K / 660 torr * 0.28 L

T₂ = 123666. 4 torr. L. K / 184.8 torr. L

T₂ = 669.2 K