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8 October, 10:52

Methanol (CH3OH) is produced commercially by the catalyzed reaction of carbon monoxide and hydrogen:

CO (g) + 2H2 (g) ⇌CH3OH (g).

An equilibrium mixture in a 1.50 L vessel is found to contain 0.0679 mol CH3OH, 0.160 mol CO, and 0.302 mol H2 at 500 K.

Required:

Calculate Kc at this temperature.

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Answers (1)
  1. 8 October, 13:49
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    Answer: Kc = 4.653

    Explanation:

    From The equation of reaction

    CO (g) + 2H2 (g) ⇌CH3OH (g)

    From the question

    [CH3OH] = 0.0679 moles

    [CO] = 0.160moles

    [H2] = 0.302

    Kc = [CH3OH]/[CO] [H2]^2

    Kc=[0.069]/[0.16]*[0.302]^2

    Kc = 4.653
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