How many grams of Na 2 CO 3 are present in 21.0 mL of a solution that is 36.0 % Na 2 CO 3 by mass? The density of the solution is 1.12 g / mL.

The answer to your question is 8.46 g of Na₂SO₄

Explanation:

Data

mass of Na₂CO₃ = ?

volume = 21 ml

percent by mass = 36%

density = 1.12 g/ml

Process

1. - Calculate the mass of the solution

density = mass / volume

solve for mass

mass = density x volume

mass = 1.12 x 21

mass = 23.52 g

2. - Calculate the mass of Na₂CO₃

Percent by mass = (mass of Na₂SO₄ / mass of solution) x 100

Solve for mass of Na₂SO₄

mass of Na₂SO₄ = Percent by mass x mass of solution/100

mass of Na₂SO₄ = 36 x 23.52/100

mass of Na₂SO₄ = 8.46 g