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2 March, 21:49

Consider the second-order decomposition of nitroysl chloride: 2NOCl (g) → 2NO (g) + Cl2 (g) At 450 K the rate constant is 15.4 atm-1s-1. How much time (in s) is needed for NOCl originally at a partial pressure of 80 torr to decay to 23.7 torr?

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  1. 3 March, 01:40
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    4.66 s

    Explanation:

    The reaction follows a second-order

    Rate = kP^2 = change in pressure/time

    k = 15.4 atm^-1s^-1

    Po = 80 torr = 80/760 = 0.1053 atm

    P = 23.7 torr = 23.7/760 = 0.0312 atm

    Change in pressure = 0.1053 - 0.0312 = 0.0741 atm

    15.4*0.0312^2 = 0.0741/time

    time = 0.0741/0.0159 = 4.66 s
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